# 2019 IUSB Programming Competition
# Round 1 Problem 1
# Find out if a year is leap or not
# Solution by Dana Vrajitoru
# Uses Python 3.6.2

# Checks if a number represents a leap year
def isLeapYear(n):
    if n % 4 != 0:
        return False
    elif n % 100 != 0:
        return True
    elif n % 400 == 0:
        return True
    else:
        return False

# Testing the function
if __name__ == '__main__':
    print("Enter a year:")
    n = int(input())
    if isLeapYear(n):
        print("yes")
    else:
        print("no")